TRANSCRIPT
- SOFA Statistics is free software: you can redistribute it and/or modify it under the terms of the GNU Affero General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version.
- Failure surface first develops right below the foundation and then slowly extends outwards with load increments. Foundation movement shows sudden jerks first (at qu1) and then after a considerable amount of movement the slip surface may reach the ground. A small amount of bulging may occur next to the foundation. Punching Shear Failure.
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Sofashallow Foundation Analysis Softwaresofa Home Loans
SoFA version 1.0
Konstantinos Nikolaou Dimitris Pitilakis
Ivan Kraus
ShallOw Foundation Analysis Software
Aristotle University of ThessalonikiThessaloniki 2012
Solved Examples
SoFA version.1.1
Solved Examples Konstantinos Nikolaou
Dimitris Pitilakis
Ivan Kraus
ShallOw Foundation Analysis Software
Aristotle University of Thessaloniki
Thessaloniki 2013
http://www.sofasoftware.weebly.com
SoFA Solved Examples Shallow Foundation Analysis Software
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Contents
Contents .................................................................................................................................................... 2
Acknowledgements ................................................................................................................................... 3
Introduction ............................................................................................................................................... 3
Example # 1 Rectangular foundation - Cohesive soil ............................................................................ 4
Example # 2 Rectangular Foundation Cohesionless soil ....................................................................... 8
Example # 3 Strip Foundation Cohesionless soil ................................................................................. 13
Example # 4 Earthquake Bearing Capacity ......................................................................................... 18
Example # 5 Settlement Calculation .................................................................................................... 24
Further Reading ...................................................................................................................................... 28
Appendix - List of symbols ..................................................................................................................... 29
SoFA Solved Examples Shallow Foundation Analysis Software
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Acknowledgements We gratefully acknowledge the contribution of Ivan Kraus (University of Osijek) to this manual.
Introduction This manual contains solved examples that were used to validate SoFA v.1.1.
For an advanced description of the algorithms and formulas used, consult the analytical users manual.
If you discover what you think is a bug, report it here. Please try to include all SoFA reports.
!
All loads considered act at the base of the footing and NOT at the theoretical
point of column fixity (for more information check out the analytical users'
manual).
SoFA does NOT calculate the footing self weight .
http://sofasoftware.weebly.com/documentation.htmlhttp://sofasoftware.weebly.com/bug-report.html
SoFA Solved Examples Shallow Foundation Analysis Software
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Example # 1 Rectangular foundation - Cohesive soil Calculate the ultimate static bearing capacity of the shallow foundation depicted in fig. 1.
Figure 1
x =y
=
154.5
1545= 0.1 m & y =
x
=1931.25
1545= 1.25 m
x = 2 x = 2 2 0.1 = 1.8 m
y = y 2 y = 4 2 1.25 = 1.5 m
= min Bx , By
= 1.5 m & = Lx , Ly
= 1.8 m
<
= + + = 19 1 + 18 2 1 + 0 = 37 kPa
For cohesive soils under undrained loading conditions according to Eurocode 7:
= . +
c = 1 + 0.2
= 1 + 0.2
1.5
1.8= 1.17
= x2 + y
2 = 202 + 1002 = 102 kN
c =1
2+
1
2 1
u=
1
2+
1
2 1
102
1.5 1.8 100= 0.89
= 5.14 100 1.17 0.89 1 + 37 = 572.2 kPa
= = 572.2 1.5 1.8 = 1545 kN
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Calculation performed using SoFA:
Click the Bearing Capacity button to access window showing the Safety Factory for Static Load Case:
SoFA Solved Examples Shallow Foundation Analysis Software
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Shallow Foundation Bearing Capacity
-------------------------------------------------------------
Kostis Nikolaou (sofa.eng@gmail.com)
Dimitris Pitilakis
Aristotle University of Thessaloniki - 2012
-------------------------------------------------------------
Geometry of the problem
* Dimentions(dx/dy) = 2.000 x 4.000 [m]
* Depth of foundation (df) = 2.000 [m]
* Depth of water level(dw) = 1.000 [m]
* Foundation base inclination(omega) = 0.000 [rad.]
* Soil inclination(beta) = 0.000 [rad.]
Design Loads - Static Load Case
* Vd = 1545.000 [kN]
* Hdx = 20.000 [kN]
* Hdy = 100.000 [kN]
* Mdx = 1931.250 [kNm]
* Mdy = 154.500 [kNm]
Soil Properties
* Type = C [C: cohessive CL: cohesionless]
* Loading= UN [D: drained UN: undrained]
* phik = 0.0 [deg.]
* ck = 0.0 [kPa] - drained shear strength
* cuk = 100.0 [kPa] - undrained shear strength
* soil Weight = 19.00 [kN/m^3]
Eccentricities (Static Load Case): ex = 0.10 ey = 1.25 [m]
Effective Dimentions: 1.500 x 1.800 [m]
Effective Area: 2.700 [m^2]
-------------------------------------------------------------
Bearing Capacity Check -- Undrained Conditions -- Static Load Case
-------------------------------------------------------------
* Eurocode 7 (2004)
sc=1.167 | ic=0.894 | bc=1.000 |
- qu_un = 573.359 [kPa]
- Vu = qu*B*L = 1548.069[kN]
- Vu/1.40 = qu*B*L/1.40 = 1105.764[kN] < 1545.000 [kN] - NOT ok -
- FS = qu/N*Aeff = 1.002
* EAK (2000)
sc=1.167 | ic=0.971 |
- qu_un = 618.989 [kPa]
- Vu = qu*B*L = 1671.272[kN]
- Vu/1.40= qu*B*L/1.40 = 1193.765[kN] < 1545.000 [kN] - NOT ok -
- FS = qu/N*Aeff = 1.082
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* DIN4017 (2006)
sc=1.167 | ic=0.894 | bc=1.000 | gc=1.000 |
- qu_un = 573.359 [kPa]
- Vu = qu*B*L = 1548.069[kN]
- Vu/1.40= qu*B*L/1.40 = 1105.764[kN] < 1545.000 [kN] - NOT ok -
- FS = qu/N*Aeff = 1.002
* Meyerhof (1953,1963)
sc=1.167 | ic=0.918 | dc=1.267 |
sq=1.000 | iq=0.918 | dq=1.000 |
- qu_un = 631.535 [kPa]
- Vu = qu*B*L = 1705.145[kN]
- Vu/1.40= qu*B*L/1.40 = 1217.961[kN] < 1545.000 [kN] - NOT ok -
- FS = qu/N*Aeff = 1.104
* Hansen (1970)
sc=0.003 | ic=0.019 | bc=0.000 | gc=0.000 | dc=0.444 |
- qu_un = 734.360 [kPa]
- Vu = qu*B*L = 1982.771[kN]
- Vu/1.40= qu*B*L/1.40 = 1416.265[kN] < 1545.000 [kN] - NOT ok -
- FS = qu/N*Aeff = 1.283
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Example # 2 Rectangular Foundation Cohesionless soil Calculate the ultimate static bearing capacity of the shallow foundation depicted in fig. 2.
x =y
=
900.8
4504= 0.2 m & y =
x
=900.8
4504= 0.2 m
x = x 2 x = 2 2 0.2 = 1.6 m
y = y 2 y = 2 2 0.2 = 1.6 m
= min Bx , By
= 1.6m & = Lx , Ly
= 1.6 m
< < + =
= + .
= f + = 18 1 + 19 1 + 0 = 37 kPa
= w f + sat w f + w
=19 2.5 2 + 20 10 (2 + 1.6 2.5)
1.6= 12.81 kN/m3
For cohesionless soils under drained loading conditions, according to Eurocode 7:
u = c c c c +
q q q q +1
2
= tan2
4+
2 = 2
4+
35
2 35 = 33.3
= 2 q 1 = 2 33.3 1 35 = 45.2
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= 1 +
= 1 +
1.6
1.6 35 = 1.57
= 1 0.3
= 1 0.3
1.6
1.6= 0.7
= x2 + y
2 = 450.42 + 450.42 = 636.96
= cos2 + sin
2 = 1.5
=2+/
1+/= 1.5 & =
2+/
1+/= 1.5
q = 1
+
= 1 636.96
4504 + 0
1.5
= 0.795
= 1
+
+1
= 1 636.96
4504 + 0
2.5
= 0.683
bq = b = 1
2= 1.0
u = 0 + 1 18 + 1 19 33.3 1.57 0.795 +1
2 1.6 12.81 45.2 0.7 0683 = 1759.3 kPa
u = u = 1759.3 1.6 1.6 = 4504 kN
Calculation performed using SoFA:
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Click the Bearing Capacity button to access the windows showing the Safety Factory for Static Load Case
and the Ultimate Bearing Capacity:
SoFA Solved Examples Shallow Foundation Analysis Software
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Shallow Foundation Bearing Capacity
-------------------------------------------------------------
Kostis Nikolaou (sofa.eng@gmail.com)
Dimitris Pitilakis
Aristotle University of Thessaloniki - 2012
-------------------------------------------------------------
Geometry of the problem
* Dimentions(dx/dy) = 2.000 x 2.000 [m]
* Depth of foundation (df) = 2.000 [m]
* Depth of water level(dw) = 2.500 [m]
* Foundation base inclination(omega) = 0.000 [rad.]
* Soil inclination(beta) = 0.000 [rad.]
Design Loads - St